Pikagirl123
Pikagirl123 Pikagirl123
  • 21-05-2018
  • Mathematics
contestada

Let f(x)=x^2+7 and g(x)=x+3/x find (g°f)(-5)

Respuesta :

CastleRook
CastleRook CastleRook
  • 31-05-2018
Given that f(x)=x^2+7 and g(x)=x+3/x
then
(g°f)(x)
=(x^2+7)+3/(x^2+7)
hence:
(g°f)(-5)=[(-5)^2+7]+3/[(-5)^2+7]
=[25+7]+3/[25+7]
=32+3/32
=32 3/32
Answer Link
throwdolbeau throwdolbeau
  • 20-05-2019

Answer:

[tex]\implies \bf\frac{35}{32}[/tex]

Step-by-step explanation:

The function f(x) is given to be : f(x) = x² +  7

Also, The function g(x) is given to be :

[tex]g(x) = \frac{x+3}{x}[/tex]

We need to find : (gof)(-5)

⇒ g(f(-5))

⇒ g((-5)² + 7)

⇒ g(32)

[tex]\implies \frac{35}{32}[/tex]

Answer Link

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