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For car A: y=20x-200 A moves 20 meters every second x, and starts 200m behind BFor Car B: y= 15x B moves 15 meters every second and starts at basisSet two equations equal to each other to find time x where they meet:20x - 200 = 15x200 = 5x x= 40A moves 20 meters every second:20x40=800m
