jaidecastillon2 jaidecastillon2
  • 22-06-2018
  • Chemistry
contestada

calculate the solubility of FeF2 in water by using 2.36 x 10 -6 as the solubility product.

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Аноним Аноним
  • 22-06-2018
FeF₂(s) ⇄ Fe²⁺ + 2 F⁻

let x = [FeF
₂]. then [Fe²⁺] = x and [F⁻] = 2x (by the reaction)

Ksp = [
Fe²⁺][F⁻]²
2.36 x 10⁻⁶ = x(2x)²
x = 8.387 × 10⁻³ M =
[FeF₂]

the solubility of
FeF₂ in water is 8.39 × 10⁻³ M
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elainalashae22
elainalashae22 elainalashae22
  • 26-05-2021

Answer:

The person above is correct

Explanation:

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