kaymmy kaymmy
  • 24-06-2018
  • Mathematics
contestada

-3(x+3y)=5 find the slop and y intercept of the line

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mkryukova19 mkryukova19
  • 24-06-2018
-3(x+3y)=5

-3x -9y =5
-9y=5+3x
y=-5/9 -(3/9)x
y = (-1/3)x-5/9

Slope = -1/3, y-intercept is (0, - 5/9)
Answer Link
AL2006
AL2006 AL2006
  • 24-06-2018
You said:  -3(x+3y) = 5

 Multiply each side by -1 :  3(x + 3y) = -5

Eliminate the parentheses on the left:  3x + 9y = -5

Subtract  3x  from each side:  9y = -3x - 5

Divide each side by  9 :  y = -1/3 x - 5/9

There's your slop-intercept form.

Slop = -1/3
Intercept = -5/9

Answer Link

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