Greenrune113 Greenrune113
  • 24-07-2018
  • Mathematics
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11.) Evaluate the integral

11 Evaluate the integral class=

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sqdancefan
sqdancefan sqdancefan
  • 24-07-2018

You can start with the indefinite integral

... ∫e^(ax)·dx = (1/a)e^(ax) +c


Then your definite integral is

[tex]\int\limits_{-3}^{10}{e^{-0.025x}}\,dx=\dfrac{-1}{.025}\left(e^{-0.025\cdot 10}-e^{-0.025\cdot(-3)}\right)\\\\=40\left(e^{.075}-e^{-0.25}\right)\\\\ \approx11.9633[/tex]

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1rstar
1rstar 1rstar
  • 25-07-2018
Hey there !

Check the attachment.
Hope it helps you :)
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