jaredlewq jaredlewq

25-07-2018
Mathematics

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If [tex] a^{2}+bx^{2} =13 [/tex], and ab=6, find the value of
a)[tex] (a+b)^{2} [/tex]
b)[tex] (a-b)^{2} [/tex]

Respuesta :

06-08-2018

[tex]a^2-b^2=13;\ ab=6[/tex]

[tex]a)\\(a+b)^2=a^2+2ab+b^2=(a^2+b^2)+2(ab)=13+2\cdot6=25\\\\b)\\(a-b)^2=a^2-2ab+b^2=(a^2+b^2)-2(ab)=13-2\cdot6=1[/tex]

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