Dramaqueen2564 Dramaqueen2564
  • 22-08-2018
  • Mathematics
contestada

Solve the quadratic equations
2(x-2)^2+5=23

Respuesta :

tchit87
tchit87 tchit87
  • 22-08-2018
2(x^2-4x+4)=18
2x^2-8x-10=0
(2x-10)(x+1)
X=5,-1
Answer Link
ktreyb
ktreyb ktreyb
  • 22-08-2018

2(x-2)² + 5 = 23

2(x² - 4x + 4) + 5 = 23

2x² - 8x + 8 + 5 = 23

2x² - 8x + 13 = 23

2x² - 8x + 13 - 23 = 0

2x² - 8x - 10 = 0

2(x² - 4x - 5) = 0

Divide both sides by 2

x² - 4x - 5 = 0

Factor:

(x - 5)(x + 1) = 0

Set both factors equal to zero:

x - 5 = 0

x = 5

x + 1 = 0

x = - 1

Your answers are x = -1, 5 or at (-1, 0) and (5, 0).

Answer Link

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