alex9271 alex9271
  • 24-08-2018
  • Mathematics
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Factor the following expression 27y3 -343

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altavistard
altavistard altavistard
  • 24-08-2018

27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.

The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)

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