alohaitsalex2578 alohaitsalex2578

21-09-2018
Mathematics

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Suppose you had 102 m of fencing to make two side-by-side enclosures as shown. what is the maximum area that you could enclosure

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tramserran tramserran

21-09-2018

Perimeter: 3w + 2L = 102 ⇒ L = -1.5w + 51

Area = w * L

= w(-1.5w + 51)

= -1.5w² + 51x

A' = -3w + 51

0 = -3w + 51

3w = 51

w = 17

Perimeter: L = -1.5w + 51 ⇒ -1.5(17) + 51 = -25.5 + 51 = 25.5

Area = width * Length

= 17 * 25.5

= 433.5

Answer: 433.5 m²

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