alohaitsalex2578 alohaitsalex2578
  • 21-09-2018
  • Mathematics
contestada

Suppose you had 102 m of fencing to make two side-by-side enclosures as shown. what is the maximum area that you could enclosure

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tramserran
tramserran tramserran
  • 21-09-2018

Perimeter: 3w + 2L = 102   ⇒  L = -1.5w + 51

Area = w * L

       = w(-1.5w + 51)

       = -1.5w² + 51x

A'    = -3w + 51

0     = -3w + 51

3w   = 51

 w  = 17

Perimeter: L = -1.5w + 51   ⇒   -1.5(17) + 51   =  -25.5 + 51   = 25.5

Area = width * Length

       =     17    *   25.5

       =          433.5

Answer: 433.5 m²

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