The equation of a line in standard form: Ax + By = C.
The point-slope form:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-3, 1) and (2, -4).
Substitute:
[tex]m=\dfrac{-4-1}{2-(-3)}=\dfrac{-5}{5}=-1\\\\y-1=-1(x-(-3))\\\\y-1=-(x+3)\\\\y-1=-x-3\qquad|+1\\\\y=-x-2\qquad|+x\\\\x+y=-2[/tex]
