flowerwolf9 flowerwolf9
  • 22-03-2019
  • Mathematics
contestada

verify formula
[tex]sin^2x+tan^2x+cos^2x =sec^2x[/tex]
​

Respuesta :

marco417chan marco417chan
  • 22-03-2019

Answer:

L.H.S=R.H.S

Step-by-step explanation:

L.H.S=sin²x+tan²x+cos²x

        =tan²x+1                                         *** sin²x+cos²x=1 ***

        =[tex]\frac{sin^{2} x}{cos^{2}x } +\frac{cos^{2} x}{cos^{2}x }[/tex]

        =[tex]\frac{sin^{2}x+cos^{2}x}{cos^{2}x }[/tex]

        =[tex]\frac{1}{cos^{2}x }[/tex]

        =sec²x                                   ***[tex]\frac{1}{cos^{2}x }[/tex]=sec²x***

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