Answer:
The standard deviation is 4.05 to the nearest hundredth
.Step-by-step explanation:
The standard deviation is given by:
[tex]s=\sqrt{\frac{\sum(x-\bar X)^2}{n} }[/tex]
The mean, [tex]\bar X=9[/tex]
This implies that;
[tex]s=\sqrt{\frac{(4-9)^2+(5-9)^2+(10-9)^2+(11-9)^2+(15-9)^2}{5} }[/tex]
[tex]s=\sqrt{\frac{25+16+1+4+36}{5} }[/tex]
[tex]s=\sqrt{\frac{82}{5} }=4.049691[/tex]
Hence the standard deviation is 4.05 to the nearest hundredth.
