AsapYeff
AsapYeff AsapYeff
  • 25-04-2019
  • Chemistry
contestada

2 Al + 3 Cl2 = 2 AlCl3
114g Al
186g Cl2
to use all of the Al how much Cl2 is required

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Аноним Аноним
  • 25-04-2019

Answer:

1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

Explanation:1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

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realteamloonies
realteamloonies realteamloonies
  • 25-04-2019

Answer:

ur mom

Explanation:

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