Answer:
The area is 4 unit²
Step-by-step explanation:
Since, the area of the triangle having vertices [tex](x_1,y_1)[/tex], [tex](x_2,y_2)[/tex] and [tex](x_3,y_3)[/tex] is,
[tex]A=\frac{1}{2}| x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]
Here, the vertices of the triangle ABC are,
A(0,2), B(8,2), and C(-4,3),
Hence, the area of the triangle is,
[tex]A=\frac{1}{2}|0(2-2) +8(3-2)-4(2-2)|[/tex]
[tex]=\frac{1}{2}|0+8-0|[/tex]
[tex]=\frac{8}{2}[/tex]
[tex]=4\text{ square unit}[/tex]
