sabrinanicole64
sabrinanicole64 sabrinanicole64
  • 21-08-2019
  • Mathematics
contestada

Let f(x) = (6x^3 – 7)^3 and g(x) = 6x^3 - 7.
Given that f(x) = (hog)(x), find h(x).

Respuesta :

Аноним Аноним
  • 21-08-2019

Answer:

h(x) = x^3.

Step-by-step explanation:

h(x) = x^3

because (h o g)(x)  = (6x^3 - 7)^3.

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gmany
gmany gmany
  • 21-08-2019

Answer:

h(x) = x³

Step-by-step explanation:

[tex]\text{We can notice:}[/tex]

[tex]g(x)=6x^3-7,\ f(x)=(\underbrace{6x^3-7}_{g(x)})^3=\bigg(g(x)\bigg)^3[/tex]

[tex]\text{If}\ f(x)=(h\circ g)(x)=h\bigg(g(x)\bigg),\ \text{then}\ h(x)=x^3[/tex]

Answer Link

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