Answer:
Valance electron in [tex]Cs^{+}[/tex] will be zero
Explanation:
We know that atomic number of cesium is 55
The electronic configuration of Cs
[tex]1s^2,2s^2,2p^6,3s^2,3p^6,3d^{10},4s^2,4p^6,4d^{10},5s^2,5p^6,6s^1[/tex]
Currently therte is one valance electron in Cs
We have given [tex]Cs^{+}[/tex] + sign indicates that cesium losses one electron means now it have no valance electron.
So valance electron in [tex]Cs^{+}[/tex] will be zero
