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I genuinely have no idea what this is asking from me

Find the solution set of each equation if the replacement sets are y: {1,3,5,7,9}
and z:{10, 12, 14, 16, 18).
11. z + 10 = 22
12. 52 = 4z
13. (15/y) = 3
14. 17 = 24-y
15. 2z - 5 = 27
16. 4(y + 1) = 40
17. 22 = (60/y)+2
18. 111 = z^2 + 11

Respuesta :

MathPhys

Step-by-step explanation:

Basically, it wants you to solve each equation for the variable.  If the answer(s) is one of the numbers in the replacement set, then that's a number in the solution set.  Otherwise, there's no solution.

For example:

11. z + 10 = 22

z = 12

12 is one of the numbers in the replacement set for z, so the solution set is {12}.

12. 52 = 4z

z = 13

13 is not one of the numbers in the replacement set for z.  There is no solution.

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