remember
(x^m)/(x^n)=x^(m-n)
(x^4/3)/(x^5/6)=
x^(4/3-5/6)=
x^(8/6-5/6)=
x^(3/6)=
x^(1/2)
second one
16 times the square root of x*x^3*x^4
first simpify parenthasees
remember
(x^m)(x^n)=x^(m+n)
(x^1)(x^3)(x^4)=x^(1+3+4)=x^8
√x^8 aka
√(x^4)^2
is x^4
16x^4 is ansre√
