Answer:
6 unit
Step-by-step explanation:
Given: Point (x,-3) and line y=3
Line: y=3 is horizontal line.
For horizontal line y is fix and x-coordinate vary
Let point on line be (x,3)
Now find distance between (x,3) and (x-3)
using distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(x-x)^2+(3+3)^2}[/tex]
[tex]d=\sqrt{6^2}[/tex]
[tex]d=6[/tex]
Hence, The distance between the point (x, −3) to the line y = 2 is 6 unit
