isyakuabdulhalim1 isyakuabdulhalim1
  • 22-10-2019
  • Physics
contestada

A body undergoing a uniformly, acceleraten motion has
two(1s,10ms) and (20s, 48ms) on the velocity time
graph of it motion. The acceleration of the body is?​

Respuesta :

skyluke89
skyluke89 skyluke89
  • 25-10-2019

Answer:

[tex]2 m/s^2[/tex]

Explanation:

The acceleration of an object is given by:

[tex]a=\frac{v-u}{\Delta t}[/tex]

where

v is the final velocity

u is the initial velocity

[tex]\Delta t[/tex] is the time interval

For the body in the problem, we have:

[tex]u=10 m/s[/tex] at t = 1 s

[tex]v=48 m/s[/tex] at t = 20 s

So the time interval is

[tex]\Delta t = 20 -1 = 19 s[/tex]

And so, the acceleration is

[tex]a=\frac{48-10}{19}=2 m/s^2[/tex]

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