milagritomiracle milagritomiracle
  • 22-10-2019
  • Mathematics
contestada

Factor completely. 6x3+39x2+63x6x3+39x2+63x


x(3x + 9)(2x + 7)

(6x + 21)(x + 3)

x(x + 3)(6x + 21)

6x3+39x2+63x6x3+39x2+63x

3x(2x + 7)(x + 3)

(3x + 9)(2x + 7)

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 23-10-2019

Answer:

[tex]3x(2x+3)(x+7)[/tex]

Step-by-step explanation:

The given polynomial expression is [tex]6x^3+39x^2+63x[/tex]

We factor the factor the greatest common factor of 3x to get;

[tex]3x(2x^2+13x+21)[/tex]

We now factor the quadratic trinomial by splitting the middle term

[tex]3x(2x^2+7x+6x+21)[/tex]

[tex]3x(2x(x+7)+3(2x+7))[/tex]

[tex]3x(2x+3)(x+7)[/tex]

The completely factored form is [tex]3x(2x+3)(x+7)[/tex]

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