Rikiyaeizor
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  • 26-10-2019
  • Mathematics
contestada

Solve y = f(x) = (2x+1)^1/2

& g(x) = x-1

Respuesta :

emily10898Emily10898
emily10898Emily10898 emily10898Emily10898
  • 26-10-2019

Answer:

f(x) = [tex]x = \frac{y^{2} - 1}{2}[/tex]

g(x) = 1

Step-by-step explanation:

y = (2x + 1)^1/2

[tex]y^{2} = 2x + 1[/tex]

[tex]y^{2} - 1 = 2x[/tex]

[tex]\frac{y^{2} - 1}{2} = x[/tex]

y = x - 1

y + 1 = x

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