teionamwhite9303 teionamwhite9303
  • 26-10-2019
  • Mathematics
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Jim is enclosing a rectangular garden with 170 feet of fencing. The length of the garden is 10 feet more than twice it's width, w. Determine the area of the garden.

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Favouredlyf Favouredlyf
  • 08-11-2019

Answer: Area = 1500 feet^2

Step-by-step explanation:

Jim is enclosing a rectangular garden with 170 feet of fencing. This means the perimeter of the rectangular garden =170 feet

Let length = x

Let width = w

The length of the garden,x is 10 feet more than twice it's width, w. This means

x =10+2w---------1

Perimeter = 2x+2w =170---------2

Putting equation 1 in equation 2,

2(10+2w) +2w= 170

20 + 4w +2w = 170

6w = 170-20=150

w = 150/6

= 25feet

Put w=25 in equation 1

x =10 +2×25= 10+50=60 feet

Area = length × width = x×w

= 60×25=1500feet^2

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