Answer:
The answer is first option i.e
[tex]\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}\\[/tex]
Step-by-step explanation:
Given:
1. angle ABC = angle GHJ
2. BC = HJ
3. angle BCA = angle HJG
Proof:
In ΔABC and ΔGHJ
[tex]\angle ABC \cong \angle GHJ \ Given\\BC \cong HJ\ \textrm{Given}\\\angle BCA \cong \angle HJG \ \textrm{Given}\\\\\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}\\[/tex]
Hence proved
