Answer:
3.16 × [tex]10^{-7}[/tex] W/[tex]m^{2}[/tex]
Explanation:
β(dB)=10 × [tex]log_{10}(\frac{I}{I_{0} })[/tex]
[tex]I_{0}[/tex]=[tex]10^{-12}[/tex] W/[tex]m^{2}[/tex]
β=55 dB
Therefore plugging into the equation the values,
55=10 [tex]log_{10}(\frac{I}{ [tex]10^{-12}[/tex]})[/tex]
5.5= [tex]log_{10}(\frac{I}{ [tex]10^{-12}[/tex]})[/tex]
[tex]10^{5.5}[/tex]= [tex]\frac{I}{10^{-12} }[/tex]
316227.76×[tex]10^{-12}[/tex]= I
I= 3.16 × [tex]10^{-7}[/tex] W/[tex]m^{2}[/tex]
