Answer:
ΔBDE ≅ΔBFK by rule ASA
Step-by-step explanation:
Given [tex]BD[/tex]≅[tex]BF[/tex]
[tex]DE[/tex]⊥[tex]BC[/tex] and [tex]FK[/tex]⊥[tex]AB[/tex]
So, ∠[tex]BDE=[/tex]∠[tex]KFB=90[/tex]°
We can see in Δ[tex]BDE[/tex] and Δ[tex]BFK[/tex]
∠[tex]DBE=[/tex]∠[tex]KBF[/tex] included angle
∠[tex]BDE=[/tex]∠[tex]KFB=90[/tex]° (Given)
Also, [tex]BD[/tex]≅[tex]BF[/tex] (Given)
From ASA
We can see two angles and one included side are same as corresponding triangle then,
ΔBDE ≅ΔBFK by rule ASA
