Answer:
[tex]\large\boxed{p<\dfrac{30}{11}\to p\in\left(-\infty,\ \dfrac{30}{11}\right)}[/tex]
Step-by-step explanation:
[tex]-7p-4>26p-94\qquad\text{add}\ 7p\ \text{to both sides}\\\\-7p+7p-4>26p+7p-94\\\\-4>33p-94\qquad\text{add 94 to both sides}\\\\-4+94>33p-94+94\\\\90>33p\qquad\text{divide both sides by 33}\\\\\dfrac{90}{33}>\dfrac{33p}{33}\\\\\dfrac{30}{11}>p\to p<\dfrac{30}{11}[/tex]
