Respuesta :

gmany

Answer:

[tex]\large\boxed{u^2+5u-6=0,\ where\ u=(x+2)}[/tex]

Step-by-step explanation:

[tex](x+2)^2+5(x+2)-6=0\\\\\text{Substitute}\ (x+2)=u:\\\\\underbrace{(x+2)}_{u}^{}^2+5\underbrace{(x+2)}_{u}-6=0\\\\u^2+5u-6=0[/tex]

samuelklenke04

Answer:

The answer is C

Step-by-step explanation: