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24-01-2020
Chemistry

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1. How many moles are in 493.4 grams of calcium phosphide?

Respuesta :

25-01-2020

Formula = Ca3P2
RAM of; Ca = 40 x 3 = 120g, P = 30 x 2 = 60g. 120 + 60 = 180g

Mole = 493.4g / 180g = 2.74mols

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