Answer:
Power = 2.16²/8 =0.58watts
Explanation:
Total resistance =[ (R1 * R2)/(R1 + R2) ] + R3 since it is combination of both parallel and series connection
Where R1 = 4ohms
R2 = 8 ohms
R3 = 12 ohms
So therefore Tr = [ (4 * 8)/(4 +8) ] + 12 = 14.67ohms
So therefore the current across the circuit = 12v/14.67ohms = 0.82 amps
So the potential across the parallel connection = 12v - (0.82 * 12 ohms)
= 12 - 9.84 = 2.16v
Since for parallel connection voltage is equally across the resistor
So: power in R2 = V²/ R2
Power = 2.16²/8 =0.58watts
