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Determine the percent composition for each of the elements in magnesium nitrate, Mg(NO3)2. Please round to the nearest whole number. First, find the molar mass of the WHOLE compound. Use whole numbers for the atomic mass. Mg(NO3)2

Respuesta :

Answer:

% Mg = 16.2 % ≈ 16 %

%N = 18.9 % ≈ 19 %

% O = 64.9 % ≈ 65 %

Explanation:

Step 1: Data given

Molar mass Mg(NO3)2 = 148 g/mol

Molar mass Mg = 24 g/mol

Molar mass N = 14 g/mol

Molar mass O = 16 g/mol

Step 2: Calculate the percent composition

% Mg = (24/148) *100%

% Mg = 16.2 % ≈ 16 %

% N = (2*14 / 148) * 100%

%N = 18.9 % ≈ 19 %

% O = (6*16/148) * 100%

% O = 64.9 % ≈ 65 %

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