Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2
[tex] \frac{ \tan(R) }{ \tan(J) } = \frac{ \frac{1}{2} }{2} [/tex]
[tex] \frac{ \tan(R) }{ \tan(J) } = \frac{1}{4} [/tex]
tan(J)=4.tan(R)
option D
