jiangtinanyp2wyu0
jiangtinanyp2wyu0 jiangtinanyp2wyu0
  • 22-03-2020
  • Mathematics
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Wallind11
Wallind11 Wallind11
  • 22-03-2020

Step-by-step explanation:

area of the cross section = πr²-π(1/2r)²

[tex] = \pi( {r}^{2} - \frac{ {r}^{2} }{4} )[/tex]

[tex] = \pi( \frac{4 {r}^{2} - {r}^{2} }{4}) [/tex]

[tex] = \pi \frac{3 {r}^{2} }{4} [/tex]

option D

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