kellerpaula kellerpaula

23-03-2020
Mathematics

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Trigonometry
Trigonometric Equations
0 ≤ x ≤ 2 π , solve the equation: sin 2x=√ 3/2

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manmeetsingh400 manmeetsingh400

23-03-2020

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amna04352 amna04352

23-03-2020

Answer:

x = π/6, π/3, 7π/6, 4π/3

Step-by-step explanation:

sin 2x = √3/2

basic angle = π/3

2x = π/3,

π - π/3 = 2π/3,

π/3 + 2π = 7π/3,

2π/3 + 2π = 8π/3

x = π/6, π/3, 7π/6, 4π/3

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