Answer:
b<-12 or b>-12
(-∞,-12]U[-12,∞)
Step-by-step explanation:
0.5b > -6 or 3b + 16 <-8 + b
I solve these separately
0.5b > -6
Divide by .5 on each side
0.5b/.5 > -6/.5
b >-12
or
3b + 16 <-8 + b
subtract b from each side
3b-b + 16 <-8 + b
-b
2b+16<-8
Subtract 16 from each side
2b+16-16<-8-16
2b< -24
Divide each side by 2
2b/2 <-24/2
b<-12
b<-12 or b>-12
