xavia125
xavia125 xavia125
  • 24-03-2020
  • Mathematics
contestada

Why is b ≠ 1 a condition for f(x) = ab^x?

Respuesta :

danielmaduroh
danielmaduroh danielmaduroh
  • 31-03-2020

Explanation:

In this case, we hace the following exponential function:

[tex]f(x)=ab^x[/tex]

Where:

[tex]a:Initial \ value \\ \\ b:the \ base[/tex]

The base [tex]b\neq 1[/tex] because 1 raised to any power leads the result of 1. That is:

[tex]1^2=1 \\ \\ 1^3=1 \\ \\ 1^{\sqrt{3}}=1 \\ \\ \\ In \ conclusion: \\ \\ 1^{n}=1, \ \text{n any real number}[/tex]

If so, then we won't get an exponential function, but a constant function:

[tex]f(x)=a[/tex]

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