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  • 24-03-2020
  • Chemistry
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How many grams of KCO3 are needed to make 20 L of a 2.5 M solution?

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Isabellandfuzzy
Isabellandfuzzy Isabellandfuzzy
  • 24-03-2020

Answer:

0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

Explanation:

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