Respuesta :

Edufirst

Answer:

  • It is not possible to produce 580 grams of rust with 120 grams of iron.

Explanation:

Here, I show you why it is not possible to produce 580 grams of rust with 120 grams of iron.

A. Molar masses of the substances:

  • Fe: 55.845g/mol 2.1488 mol
  • O₂: 15.999 g/mol
  • Fe₂O₃: 159,69 g/mol 3.6320 mol

B. The chemical equation is:

     4Fe   +   3O₂   →   2Fe₂O₃

How many grams of iron are there in 580 grams of rust (Fe₂O₃) ?

1. Convert the mass of Fe₂O₃ into number of moles:

  • moles = mass in grams / molar mass
  • moles = 580g / (159.69 g/mol) = 3.6320 mol of Fe₂O₃

2. Calculate the number of moles of Fe in 3.6320 mol of Fe₂O₃

There are 2 moles of Fe per mole of Fe₂O₃:

  • 2 mol Fe / mol Fe₂O₃ × 3.6320 mol Fe₂O₃ = 7.2640 mol Fe

3. Calculate the mass of 7.2640 moles of Fe:

  • mass = number of moles × atomic mass
  • mass = 7.2640 mol × 55.845 g/mol = 405.66 g

Thus, 120 grams of Fe is too little to produce the mentioned amount of rust; you need about 406 grams of Fe to produce 580 grams of rust.

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