alexissaunders4468 alexissaunders4468
  • 25-03-2020
  • Mathematics
contestada

If you start at vertex A and use the "shortest route" algorithm, what would be the second path to

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lukman4real lukman4real
  • 30-03-2020

Answer:

Shortest distance=|AC|/[tex]\sqrt[2]{2}[/tex].

Kindly find the attached for the figure

Step-by-step explanation:

This problem can be addressed using right-angled,

Let have right angle triangle with the shortest distance=hypotenuse;

hypotenuse=|AC|

using pythagoras theorem, we have

|AC|^2=|AB|^2+|BC|^2

Let |AB|=|BC|

|AC|^2=2|AB|^2

|AB|=|AC|/[tex]\sqrt[2]{2}[/tex]

Shortest distance=|AC|/[tex]\sqrt[2]{2}[/tex]

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