Answer:
Step-by-step explanation:
[tex]\frac{-1}{4}(\frac{-1}{2}x-\frac{3}{4})-\frac{1}{2}(\frac{3}{4}x+\frac{1}{8})\\\\=\frac{-1}{4}*\frac{-1}{2}x-\frac{-1}{4}*\frac{3}{4}-\frac{1}{2}*\frac{3}{4}x-\frac{1}{2}*\frac{1}{8}\\\\=\frac{1}{8}x+\frac{3}{16}-\frac{3}{8}x-\frac{1}{16}\\\\=\frac{1}{8}x-\frac{3}{8}x+\frac{3}{16}-\frac{1}{16}\\\\=\frac{(1-3)x}{8}+\frac{3-1}{16}\\\\=\frac{-2}{8}x+\frac{2}{16}\\\\=\frac{-1}{4}x+\frac{1}{4}[/tex]
