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26-03-2020
Mathematics

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5 - sqrt 2 / sqrt 3 how can you write the expression with a rationalized denominator

5 sqrt 2 sqrt 3 how can you write the expression with a rationalized denominator class=

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26-03-2020

[tex]\dfrac{5 - \sqrt 2}{\sqrt{3}} \cdot \dfrac{\sqrt{3}}{\sqrt 3} = \dfrac{5 \sqrt{3} - \sqrt{2} \sqrt{3}}{3} = \dfrac{5 \sqrt 3 - \sqrt 6}{3}[/tex]

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