The first step in solving this is to substitute x with 3 and y with 2, so that [tex]\frac{1}{3} x^{2} +5.2y[/tex] becomes [tex] \frac{1}{3} (3)^{2} +5.2(2)[/tex] Then simply solve using the order of operations. First exponents (there are no parentheses) [tex] \frac{1}{3} 9 +5.2(2)[/tex] Then multiply and divide [tex]3+10.4[/tex] And finally add and subtract [tex]13.4[/tex] Therefore the value of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4
