matthinds
matthinds matthinds
  • 21-04-2020
  • Mathematics
contestada

Solve: 18^x^2+4x+4 = 18^9x+18

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 22-04-2020

Answer:

  x = -2 or +7

Step-by-step explanation:

We presume you want to solve ...

  18^(x^2 +4x +4) = 18^(9x +18)

Equate exponents of the same base and put the quadratic in standard form.

  x^2 +4x +4 = 9x +18

  x^2 -5x -14 = 0

  (x -7)(x +2) = 0

Values of x that make these factors zero are 7 and -2.

The solutions are x=-2 or x = 7.

Answer Link
chocolatecake89 chocolatecake89
  • 12-05-2021

Answer:

c

Step-by-step explanation:

got it right on edge

Answer Link

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