moonp6096 moonp6096
  • 22-04-2020
  • Mathematics
contestada

If LaTeX: \frac{12x^2-6x}{3}=ax^2+bx+c,12 x 2 − 6 x 3 = a x 2 + b x + c , what is the value of LaTeX: aa?

Respuesta :

Newton9022 Newton9022
  • 27-04-2020

Answer:

[tex]a=4[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{12x^2-6x}{3}=ax^2+bx+c[/tex]

Simplifying the left hand side

[tex]\dfrac{12x^2-6x}{3}=\dfrac{12x^2}{3}-\dfrac{6x}{3}=4x^2-2x[/tex]

Comparing our result with the right hand side

[tex]4x^2-2x=ax^2+bx+c\\4x^2=ax^2\\a=4[/tex]

The value of a is 4.

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