roseluv2222 roseluv2222
  • 25-04-2020
  • Chemistry
contestada

What is the volume of 28.0g of propane at 15C degrees, and 1.2 atm?

Respuesta :

kobenhavn kobenhavn
  • 03-05-2020

Answer: Volume of 28.0 g of propane is 15.0 Liters

Explanation:

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 1.2 atm

V = Volume of gas = ?

n = number of moles=[tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{28.0g}{44.1g/mol}=0.635mol[/tex]

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature = [tex]15^0C=(15+273)K=288K[/tex]

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{0.635\times 0.0821L atm/K mol\times 288K}{1atm}=15.0L[/tex]

Thus volume of 28.0 g of propane is 15.0 Liters

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