syifa01
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  • 21-08-2016
  • Mathematics
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2/3×2log64-1/2×2log16

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Аноним Аноним
  • 21-08-2016
[tex] \dfrac{2}{3} *2log 64 - \dfrac{1}{2} *2log 16 [/tex]

[tex] \dfrac{2}{3} *2log \ 2^6 - \dfrac{1}{3} *2 \ log \ 2^4 [/tex]

[tex] \dfrac{2}{3} *(6)*2log2 - \dfrac{1}{2} *(4)*2log2 [/tex]

[tex]4*(1) - 2*(1) [/tex]

[tex]= 2[/tex]
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