heathercole822
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  • 25-05-2020
  • Mathematics
contestada

What is the inverse of Y = 2x^2 - 8

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SPJ SPJ
  • 25-05-2020

Answer:

[tex]y = \pm \sqrt{\frac{x+8}{2} }[/tex]

Step-by-step explanation:

When you're writing the inverse equation, switch the position of the x and y and then solve for y.

[tex]x = 2y^{2} - 8 \\2y^{2} = x+8 \\y^{2} = \frac{x+8}{2}\\ y = \pm \sqrt{\frac{x+8}{2} }[/tex]

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