Seudónimo Seudónimo
  • 22-06-2020
  • Mathematics
contestada

Last question! I need help with showing my work! I already have the answer in the attached image below, thanks!

Last question I need help with showing my work I already have the answer in the attached image below thanks class=

Respuesta :

jimrgrant1 jimrgrant1
  • 22-06-2020

Answer:

see explanation

Step-by-step explanation:

Given

[tex]\sqrt{\frac{4x^2}{3y} }[/tex]

= [tex]\frac{\sqrt{4x^2} }{\sqrt{3y} }[/tex]

= [tex]\frac{2x}{\sqrt{3y} }[/tex]

Rationalise the denominator by multiplying the numerator/ denominator by [tex]\sqrt{3y}[/tex]

Note that [tex]\sqrt{a}[/tex] × [tex]\sqrt{a}[/tex] = a

= [tex]\frac{2x}{\sqrt{3y} }[/tex] × [tex]\frac{\sqrt{3y} }{\sqrt{3y} }[/tex]

= [tex]\frac{2x\sqrt{3y} }{3y}[/tex]

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