Answer:
-8, 3
Step-by-step explanation:
[tex]f(x) = (x - 3)(x + 8) \\ plug \: f(x) = 0 \\ (x - 3)(x + 8) = 0 \\ x - 3 = 0 \: or \: x + 8 = 0 \\ x = 3 \: or \: x = - 8 \\ \therefore \: - 8, \: 3 \: are \: zeros \: [/tex]
