esmeraldas2002 esmeraldas2002

25-06-2020
Mathematics

contestada

I’ll mark you Brainly-ist if you’re correct.

Write the log5 19/x as the difference between two logarithms.
Log5 19/x = log5( ) -log5 x

Respuesta :

wegnerkolmp2741o wegnerkolmp2741o

25-06-2020

Answer:

log5 19 - log5 x

Step-by-step explanation:

log5 19/x

log ( a/b) = log a - log b

log5 19 - log5 x

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